MHT CET20225 Aug 2022Evening ShiftPhysicsOscillationsActual
A simple pendulum with bob of mas ' m ' and conducting wire of length ' L ' swings under gravity through an angle ' '. The component of earth's magnetic field in the direction perpendicular to swing is ' B '. Maximum e.m.f. induced across the pendulum is ( g = acceleration due to gravity)
Options
- ABL ( 2 )( gL )
- B2 BL ( 2 )( gL )^2
- C2 BL ( 2 )( gL )^ 3 / 2
- D2 BL ( 2 )( gL )^ 1 / 2
Correct answer
D. 2 BL ( 2 )( gL )^ 1 / 2
Step-by-step solution
We have, h = L (1- ) Maximum velocity at equilibrium position is given by, aligned & v ^2=2 gh =2 gL (1- )=2 gL (2 ^2 ( 2 ) ) & v =2 ( 2 ) gL aligned Thus Maximum potential difference, V _ = BvL =2 BL ( 2 ) gL