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MHT CET202124 Sep 2021Evening ShiftPhysicsOscillationsActual

The displacement of a particle performing S.H.M is given by x=5 (3 t+3) , where x is in cm and t is in second. The maximum acceleration of the particle will be

Options

  1. A15 ~cm ~s ⁻²
  2. B30 ~cm ~s ⁻²
  3. C45 ~cm ~s ⁻²
  4. D90 ~cm ~s ⁻²

Correct answer

C. 45 ~cm ~s ⁻²

Step-by-step solution

x=5 (3 t+3) Standard equation of S.H.M. is x=A ( t+ ) A =5 ~cm , =3 rad / s Maximum acceleration a _ m = A ^2=5 (3)^2=5 9=45 ~cm ~s ⁻²

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