MHT CET202124 Sep 2021Morning ShiftPhysicsOscillationsActual
A bob of simple pendulum of mass 'm' perform SHM with amplitude ' A ' and period ' T '. Kinetic energy of pendulum at displacement x = A 2 will be
Options
- A2 m ^2 A 3 T^2
- B3 ~m ^2 ~A 2 ~T
- C2 ~m A ^2 3 ~T
- D3 m ^2 A^2 2 T^2
Correct answer
D. 3 m ^2 A^2 2 T^2
Step-by-step solution
aligned & Kinetic energy = 1 2 ~m ^2 ( ~A ^2- x ^2 ) & At x = A 2 , & K.E. = 1 2 ~m ^2 ( 3 4 ~A ^2 )= 3 8 ~m ^2 ~A ^2 & = 3 8 ~m ( 2 T )^2 A ^2 & = 3 8 ~m 4 ^2 ~T ^2 A ^2 & = 3 ~m ^2 ~A ^2 2 ~T ^2 aligned