An object executes SHM along x -axis with amplitude 0.06 ~m . At certain distance ' x ' metre from mean position, it has kinetic energy 10 ~J and potential energy 8 ~J . The distance ' x ' will be

Step-by-step solution

aligned & A =0.06 ~m , ~K . E .=10 ~J , P . E .=8 ~J & Total energy T.E. =10+8=18 ~J & P.E. = 1 2 kx ^2, TE = 1 2 kA ^2 & P . E T . E = x ^2 ~A ^2 = 8 18 = 4 9 & x A = 2 3 or x = 2 3 ~A = 2 3 0.06=0.04 ~m aligned