A mass 0.4 ~kg performs S.H.M. with a frequency 16 Hz . At a certain displacement it has kinetic energy 2 ~J and potential energy 1.2 ~J . The amplitude of oscillation is

Step-by-step solution

aligned & m =0.4 ~kg , f = 16 Hz , K E =2 ~J , P.E. =1.2 ~J & =2 f =2 16 =32 rad / s aligned Total energy T.E. =2+1.2=3.2 ~J aligned & TE = 1 2 ~m ^2 ~A ^2 & A ^2= 2( TE ) m ^2 = 2 3.2 0.4 (32)^2 = 6.4 0.4 (32)^2 = 16 (32)^2 & A = 4 32 = 1 8 =0.125 ~m aligned