MHT CET202120 Sep 2021Morning ShiftPhysicsOscillationsActual
A particle executes S.H.M. of period 2 3 along a straight line 4 ~cm long. The displacement of the particle at which the velocity is numerically equal to the acceleration is
Options
- A2 ~cm
- B1 ~cm
- C4 ~cm
- D3 ~cm
Correct answer
B. 1 ~cm
Step-by-step solution
Acceleration, a= ^2 x Velocity, v= A^2-x^2 aligned & ^2 x = A ^2- x ^2 & ^2 x ^2= A ^2- x ^2 & 3 x ^2= A ^2- x ^2 ( = 2 T = 3 ) & 4 x ^2= A ^2 & x = A 2 = 2 2 =1 ~cm aligned