A particle starts from mean position and performs S.H.M. with period 6 second. At what time its kinetic energy is 50 % of total energy? ( 45^ = 1 2 )

Step-by-step solution

T=6 ~sec 1 2 m ² (A²-x² )= 1 2 ( 1 2 m ² A² .)A²-x²= A² 2 x²= A² 2 x= A 2 A 2 =A t=A 2 T t 1 2 = 2 6 t= 3 t 4 t= 3 t t= 3 4 =0.75 sec