MHT CET202019 Oct 2020Evening ShiftPhysicsOscillationsActual
A bob of a simple pendulum has mass 'm' and is oscillating with an amplitude 'a'. If the length of the pendulum is 'L' then the maximum tension in the string is [ 0^ =1, ~g = . acceleration due to gravity ]
Options
- Amg [1+ ( a L )² ]
- Bmg [1- ( L a )² ]
- Cmg [1+ ( L a )² ]
- Dmg [1- ( a L )² ]
Correct answer
A. mg [1+ ( a L )² ]
Step-by-step solution
(B) tension in the string is maximum when the bob passes through the mean position. T _ = mg + mV ² ~L ...(1) In S.H.M. velocity at the mean position is given by V = a For simple pendulum T =2 L g = 2 T = g L V=a g L or V²=a² g L Putting this value of V ² in Eq .(1) we get T _ = mg [1+ ( a L )² ]