A spring executes S.H.M. with mass 10 ~kg attached to it. The force constant of the spring is 10 ~N / m . If at any instant its velocity is 40 ~cm / s , the displacement at that instant is (Amplitude of S.H.M. =0.5 ~m )

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Correct answer: A. 0.3 ~m

array l V=0 A²-x² = k m A²-x² k=10 ~N / m , m =10 ~kg , A=0.5 ~m V=40 ~cm / s =0.4 ~m / s array Substituting the values and solving we get x =0.3 ~m

A spring executes S.H.M. with mass 10 ~kg attached to it. The force constant of the spring is 10 ~N / m . If at any instant its velocity is 40 ~cm / s , the displacement at that instant is (Amplitude of S.H.M. =0.5 ~m )

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