MHT CET202014 Oct 2020Evening ShiftPhysicsOscillationsActual
A particle performs S.H.M. from the mean position. Its amplitude is 'A' and total energy is 'E'. At a perticular instant its kinetic energy is 3 E 4 . The displacement of the particle at that instant is
Options
- AA
- BA 8
- CA 4
- DA 2
Correct answer
D. A 2
Step-by-step solution
Total energy = E = 1 2 ~m ² ~A ² When kinetic energy is 3 E 4 , its potential energy is ( E - 3 E 4 )= E 4 Dividing Eq.(1) by Eq.(2), 4= A² x² x= A 2