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MHT CET202014 Oct 2020Morning ShiftPhysicsOscillationsActual

The displacement of the particle executing linear S.H.M. is x =0.25 sin (11 t +0.5) m . The period of S.H.M. is ( = 22 7 )

Options

  1. A2 7 S
  2. B4 7 ~S
  3. C3 7 ~S
  4. D1 7 S

Correct answer

B. 4 7 ~S

Step-by-step solution

Comparing with standard equation of S.H.M. x=A ( t+ ) we get =11 T= 2 = 2 22 11 7 = 4 7

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