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MHT CET202014 Oct 2020Morning ShiftPhysicsOscillationsActual

A small mass 'm' is suspended at the end of a wire having (negligible mass) length 'L' and cross-sectional area 'A'. The frequency of oscillation for the S.H.M. along the vertical line is ( Y = Young's modulus of the wire)

Options

  1. A1 2 ( YA mL )^ 1 2
  2. B2 YA mL
  3. CYA 2 mI
  4. D2 ( YA mL )^ 1 2

Correct answer

A. 1 2 ( YA mL )^ 1 2

Step-by-step solution

If x is the extension of the wire then P= ( Y A L ) x F=k x where k= Y A L frequency of oscillation is given by f= 1 2 k m = 1 2 Y A mL

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