MHT CET202013 Oct 2020Evening ShiftPhysicsOscillationsActual
A body performs linear simple harmonic motion of amplitude 'A". At what displacement from the mean position, the potential energy of the body is one fourth of its total energy?
Options
- AA 3
- BA 2
- C3 ~A 4
- DA 4
Correct answer
B. A 2
Step-by-step solution
Total energy = 1 2 KA ² Potential energy = 1 2 kx ² If P.E. = 1 4 ( ~K . E .) then 1 2 kx ²= 1 4 ( 1 2 kA ² ) x²= A² 4 or x= A 2