A simple pendulum of length 'L' is suspended from a roof of a trolley. A trolley moves in horizontal direction with an acceleration 'a'. What would be the period of oscillation of a simple pendulum? [ g is acceleration due to gravity]

Step-by-step solution

T =2 L g When the trolley has 18. (A) f₁ 24 = 1.5-1 1.5 9 / 8 -1 = 0.5 1.5 1.16 -1 = 0.5 1.16 0.34 f ₁=24 1 2 1.16 0.34 = 12 1.16 0.34 =40.94 ~cm acceleration is the resultant of a and g _ W where g is the effective value of acceleration due to gravity. a ' in horizontal direction, the effective value = are at right angles to each other. Hence aligned T &=2 L (a²+g² )^ 1 2 = 2 L (a²+g² )^ 1 2 &=2 L (a²+g² )^ - 1 4 aligned