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MHT CET202012 Oct 2020Morning ShiftPhysicsOscillationsActual

A mass 'M' is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes S.H.M. of period T . If the mass is increased by 'm', the time period becomes 5 ~T ^ 3 . What is the ratio ( M m ) ?

Options

  1. A25 9
  2. B16 9
  3. C9 25
  4. D9 16

Correct answer

D. 9 16

Step-by-step solution

T=2 M k ; 5 T 3 =2 M+m k 5 3 2 M k =2 M+m k 25 9 M k = M+m k 25 9 M=M+m Dividing by M, 25 9 =1+ m M m M = 25 9 -1= 16 9 M m = 9 16

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