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MHT CET2018PhysicsOscillations

The path length of oscillation of simple pendulum of length 1 m is 16 cm . Its maximum velocity is g = π 2 m s -2

Options

  1. A2 π   c m   s - 1
  2. B4 π   c m   s - 1
  3. C8 π c m s - 1
  4. D16 π   c m   s - 1

Correct answer

C. 8 π c m s - 1

Step-by-step solution

Path length = 1 6 cm ∴ Amplitude A = 8 cm Period T = 2 π l g = 2 π l π 2 = 2 s = 2 π × 1 π = 2 s Maximum velocity V max = = a ω = A × 2 π Τ = 8 × 2 π 2 = 8 π c m s - 1

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