MHT CET2018PhysicsOscillations
A mass is suspended from a vertical spring which is executing S.H.M. of frequency 5 Hz . The spring is unstretched at the highest point of oscillation. The maximum speed of the mass is [acceleration due to gravity g = 10 m s - 2 ]
Options
- A2 π   m   s - 1
- Bπ m s - 1
- C1 2 π   m   s - 1
- D1 π   m   s - 1
Correct answer
D. 1 π   m   s - 1
Step-by-step solution
T = 2 π m k n = 1 2 π k m 25 = 1 4 π 2 k m k = 100 π 2 m k A = m g A = m g k V max = ω A = 2 π T A = 2 π n A = 2 π × 5 × m g k V max = 10 π × m × 10 100 π 2 m = 1 π   m   s - 1