MHT CET2016PhysicsOscillations
The bob of a simple pendulum performs SHM with period T in air and with period T 1 in water. Relation between T a n d T 1 is (neglect friction due to water, density of the material of the bob is 9 8 × 10 3 k g / m 3 , density of water is 1 g / c c )
Options
- AT 1 = 3 T
- BT 1 = 2 T
- CT 1 = T
- DT 1 = T 2
Correct answer
A. T 1 = 3 T
Step-by-step solution
T = 2 π l g e f f In air g e f f = g where as in water g e f f = g σ - ρ σ = 9.8 9 8 × 10 3 - 10 3 9 8 × 10 3 = 9.8 9 8 - 1 9 8 = 9.8 × 1 8 × 8 9 = 9.8 9 ∴ T 1 = 2 π l g e f f = 2 π 9 l g ⇒ T 1 = 9 T = 3 T