A particle performing SHM has time period 2 3 and path length 4 ~cm . The displacement from mean position at which acceleration is equal to velocity is

Step-by-step solution

Velocity v= A²-x² and acceleration = ² x Given, A²-x² = ² x or A²-x² = x Given, T= 2 3 and = 2 T = 3 Substituting the value of in Eq (i), we get A²-x² = 3 x A=2 x aligned As amplitude &= path length 2 =2 ~cm x=1 ~cm aligned