Ratio of kinetic energy at mean position to potential energy at A / 2 of a partide performing SHM

Step-by-step solution

Kinetic energy K= 1 2 m ² (A²-y² ) At mean position y=0 K= 1 2 m ² (A² ) Potential energy U= 1 2 m ² y²U at y= A 2 U= 1 2 m A² 4 ² Dividing Eq (i) by Eq (ii), we get KE U = 4 1