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MHT CET2007PhysicsOscillations

The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B . A man jumps to a height of 2 ~m on the surface of A . What is the height of jump by the same person on the planet B ?

Options

  1. A6 ~m
  2. B2 3 ~m
  3. C2 / 9 ~m
  4. D18 ~m

Correct answer

D. 18 ~m

Step-by-step solution

It is given that, acceleration due to gravity on planet A is 9 times the acceleration due to gravity on planet B ie, g_ A =9 g_ B From third equation of motion v²=2 g h At planet A, h_ A = v² 2 g_ A At planet B, h_ B = v² 2 g_ B Dividing Eq. (ii) by Eq. (iii), we have h_ A h_ B = g_ B g_ A From Eq. (i), g_ A =9 g_ B h_ A h_ B = g_ B 9 g_ B = 1 9 or h_ B =9 h_ A =9 2=18 ~m ( h_ A =2 ~m )

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