The angle of minimum deviation produced by a thin prism in air is ₁ . What will be the minimum deviation ( ₂ ) if the prism is immersed in liquid ? [ ^a n_g = 3 2 , ^a n_ = 1 3 ]

Step-by-step solution

For a thin prism, the angle of minimum deviation is given by = (n_ rel - 1)A , where n_ rel is the refractive index of the prism relative to the surrounding medium and A is the angle of the prism. When the prism is in air, the deviation ₁ is: ₁ = ( ^a n_g - 1)A Substituting ^a n_g = 3 2 : ₁ = ( 3 2 - 1 )A = A 2 When the prism is immersed in the liquid, the relative refractive index of the glass with respect to the liquid is: ^ n_g = ^a n_g ^a n_ = 3 2 1 3 = 9 2 The new deviation ₂ in the liquid is: ₂ = ( ^ n_g - 1)