A particle executes linear S.H.M. along the principal axis of a convex lens of focal length 8 ~cm . The mean position of oscillation is at 14 ~cm from the lens with amplitude 1 ~cm . The amplitude of oscillating image of the particle is nearly

Step-by-step solution

f =8 ~cm , when the particle is at mean position, u =-14 ~cm aligned & 1 ~V = 1 f + 1 u = 1 8 - 1 14 = 3 56 & V = 56 3 19 ~cm aligned When the particle is at one of the extreme positions its distance from the lens is 14+1=15 ~cm u =-15 ~cm Again, 1 ~V = 1 f + 1 u = 1 8 - 1 15 = 7 120 v = 120 7 17 ~cm Amplitude of the image =19-17=2 ~cm