MHT CET202617 April 2026Evening ShiftPhysicsRotational MotionActual
A solid sphere of radius R and mass M is rotating about its diameter. The moment of intertia of the solid sphere rotating about an axis at a distance R 3 from the centre and parallel to that diameter is
Options
- A11 15 MR^2
- B13 20 MR^2
- C23 45 MR^2
- D47 45 MR^2
Correct answer
C. 23 45 MR^2
Step-by-step solution
The moment of inertia of a solid sphere of mass M and radius R about its diameter (an axis passing through its centre) is given by: I_ cm = 2 5 MR^2 Using the parallel axis theorem, the moment of inertia I about an axis parallel to the diameter and at a distance d = R 3 from the centre is: I = I_ cm + Md^2 Substituting the values: I = 2 5 MR^2 + M ( R 3 )^2 I = 2 5 MR^2 + 1 9 MR^2 I = ( 18 + 5 45 )MR^2 I = 23 45 MR^2