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MHT CET20249 May 2024Evening ShiftPhysicsRotational MotionActual

A particle of mass ' m ' is rotating in a circular path of radius ' r '. Its angular momentum is ' L '. The centripetal force acting on it is ' F '. The relation between ' F ', ' L ', ' r ' and ' m ' is

Options

  1. AF = L mr ^2
  2. BL = m ^2 Fr ^2
  3. CL ^2 ~m = Fr ^3
  4. DF L ^3 = mr ^2

Correct answer

C. L ^2 ~m = Fr ^3

Step-by-step solution

Angular momentum, L = rp = rp for U.C.M. [ =.90^ ] L ^2 mr ^3 = r ^2 ~m ^2 v ^2 mr ^3 = mv ^2 r Given, Centripetal force, F= m^2 r L ^2 mr ^3 = F ~L ^2 ~m = Fr ^3

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