MHT CET202124 Sep 2021Evening ShiftPhysicsRotational MotionActual
The moment of inertia of a thin uniform rod of mass ' M ' and length ' L ' about an axis passing through a point at a distance L 4 from one of its ends and perpendicular to the length of the rod is
Options
- AML ^2 48
- B7 ML ^2 48
- C5 ML ^2 48
- D9 ML ^2 48
Correct answer
B. 7 ML ^2 48
Step-by-step solution
The moment of inertia of the rod about an axis passing through the center and perpendicular to its length is given by I ₀= ML ^2 12 Hence by parallel axis theorem, I = I ₀+ M ( L 4 )^2= ML ^2 12 + ML ^2 16 = 7 ML ^2 48