MHT CET202120 Sep 2021Evening ShiftPhysicsRotational MotionActual
A disc of radius 0.4 ~m and mass 1 ~kg rotates about an axis passing through its center and perpendicular to its plane. The angular acceleration of the disc is 10 rad / s ^2 . The tangential force applied to the rim of the disc is
Options
- A4 ~N
- B1 ~N
- C2 ~N
- D8 ~N
Correct answer
C. 2 ~N
Step-by-step solution
R =0.4 ~m , M =1 ~kg , =10 rad / s ^2 Moment of inertia, I = MR ^2 2 = 1 (0.4)^2 2 =0.08 ~kg ~m ^2 Torque, = RF = I F = I R = 0.08 10 0.4 =2 ~N