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MHT CET202014 Oct 2020Morning ShiftPhysicsRotational MotionActual

The moment of inertia of a thin uniform rod about a perpendicular axis passing through one of its ends is 'I'. Now, the rod is bent in a ring and its moment of inertia about diameter is ' I ₁^ . Then I I ₁ is

Options

  1. A8 ² 3
  2. B11 ² 3
  3. C4 ² 3
  4. D² 3

Correct answer

A. 8 ² 3

Step-by-step solution

If M is the mass of the rod and L is its length, then I= M L² 3 Radius of the circular ring is given by aligned 2 r=L &= L 2 I₁ &= M r² 2 = M 2 L² 4 ² 1 I₁ &= 8 ² 3 aligned

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