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MHT CET20192 May 2019Morning ShiftPhysicsRotational MotionActual

A uniform rod of length ‘ 6 L ’ and mass ‘ 8 m ’ is pivoted at its centre ‘ C ’. Two masses ‘ m ’ and ‘ 2 m ’ with speed 2 v , and v , as shown strikes the rod and stick to the rod. Initially, the rod is at rest. Due to impact, if it rotates with angular velocity ‘ ω 1 ’, then ‘ ω ’ will be.

Options

  1. Av 5 L
  2. BZero
  3. C8 v 6 L
  4. D11 v 3 L

Correct answer

A. v 5 L

Step-by-step solution

From angular momentum conservation: 2 m v L + m 2 v 2 L = 8 m 6 L 12 2 + 2 m L 2 + m 2 L 2 ω ⇒ ω = v 5 L

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