A solid sphere rolls down from top of inclined plane, 7 m high, without slipping. Its linear speed at the foot of plane is g = 10 m s 2

Step-by-step solution

Given, height of inclined plane, h = 7m G = 10 m s 2 By conservation of energy, Potential energy lost by the solid sphere in rolling down the inclined plane = Kinetic energy gained by the sphere. m g h = 1 2 m v 2 + 1 2 l ω 2 = 1 2 m v 2 + 1 2 . 2 5 m R 2 v R 2 = 1 2 m v 2 + 1 5 m v 2 m g h = 7 10 m v 2 ∴ v 2 = 10 7 g h ⇒ v = 10 7 g h = 10 7 × 10 × 7 = 100 m s