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NEET2026PhysicsChapterActual

A uniform cylindrical rod of cross-sectional area S is placed on a frictionless horizontal surface. Two equal and opposite forces, each of magnitude F , are applied outwardly along the length of the rod at its two ends. The tensile stress produced in the rod is:

Options

  1. AZero
  2. BF 2S
  3. CF S
  4. D2F S

Correct answer

C. F S

Step-by-step solution

Consider a cross-section of the rod at any point along its length. Since the rod is in equilibrium under the action of two equal and opposite forces F at its ends, the net force on any part of the rod is zero. The internal restoring force (tension) T developed at any cross-section must balance the external force F applied at the ends. Thus, T = F . Tensile stress is defined as the internal restoring force per unit cross-sectional area. Tensile stress = T S = F S . Answer: F S

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