In a laboratory experiment to verify Ohm's law, a student measures the potential difference across a nichrome wire as V = (90 1.8) V and the current passing through it as I = (3.0 0.15) A . The calculated resistance of the wire, taking into account the limits of error, is:

Step-by-step solution

Given V = 90 1.8 V and I = 3.0 0.15 A . From Ohm's law, the resistance is given by R = V I . Substituting the nominal values: R = 90 3.0 = 30 The maximum fractional error in resistance is the sum of the fractional errors in voltage and current: R R = V V + I I R 30 = 1.8 90 + 0.15 3.0 R 30 = 0.02 + 0.05 = 0.07 The absolute error in resistance is: R = 30 0.07 = 2.1 Thus, the calculated resistance with limits of error is (30 2.1) . Answer: (30 2.1)