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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

A circular coil having magnetic moment μ is placed in a uniform...

A circular coil having magnetic moment μ⃗\vec{\mu} is placed in a uniform magnetic field B⃗\vec{B}. If the coil is in a state of unstable equilibrium, what is its magnetic potential energy?

Options

  1. A−μB-\mu B
  2. B+μB+\mu B
  3. CZero
  4. D+μB2+\dfrac{\mu B}{2}

Correct answer

B. +μB+\mu B

Step-by-step solution

The magnetic potential energy of a magnetic dipole in a uniform magnetic field is given by U=−μ⃗⋅B⃗=−μBcos⁡θU = -\vec{\mu} \cdot \vec{B} = -\mu B \cos \theta, where θ\theta is the angle between the magnetic moment μ⃗\vec{\mu} and the magnetic field B⃗\vec{B}.

For the coil to be in equilibrium, the net torque acting on it must be zero. The torque is given by τ⃗=μ⃗×B⃗\vec{\tau} = \vec{\mu} \times \vec{B}, which implies τ=μBsin⁡θ=0\tau = \mu B \sin \theta = 0. This gives θ=0∘\theta = 0^{\circ} or θ=180∘\theta = 180^{\circ}.

In a state of unstable equilibrium, the potential energy is maximum. This occurs when θ=180∘\theta = 180^{\circ}.

Substituting θ=180∘\theta = 180^{\circ} in the expression for potential energy:

U=−μBcos⁡(180∘)=−μB(−1)=+μBU = -\mu B \cos(180^{\circ}) = -\mu B (-1) = +\mu B

Answer: +μB+\mu B
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