Consider the circuit shown in the given figure. What will be the charge on the 5 F capacitor in the steady state?

Step-by-step solution

In the steady state, the capacitor acts as an open circuit. Thus, no current flows through the middle branch containing the 5 F capacitor and the 4 resistor. The steady current I flows only through the 2 and 3 resistors. The equivalent resistance of the circuit is: R_ eq = 2 + 3 = 5 The current in the circuit is: I = 10 5 = 2 A The potential difference across the 3 resistor is: V = I 3 = 2 3 = 6 V Since the capacitor branch is in parallel with the 3 resistor, the potential difference across the capacitor branch is