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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

An electric potential of 3 × 10^4 V is produced at a distance of 60...

An electric potential of 3×104 V3 \times 10^4 \text{ V} is produced at a distance of 60 cm60 \text{ cm} from an isolated point charge in air. The magnitude of the point charge is [Take 14πε0=9×109 N m2 C−2]\left[\text{Take } \dfrac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \text{ N m}^2 \text{ C}^{-2}\right] :

Options

  1. A2×10−4 C2 \times 10^{-4} \text{ C}
  2. B1.2×10−6 C1.2 \times 10^{-6} \text{ C}
  3. C2×10−6 C2 \times 10^{-6} \text{ C}
  4. D2×10−5 C2 \times 10^{-5} \text{ C}

Correct answer

C. 2×10−6 C2 \times 10^{-6} \text{ C}

Step-by-step solution

The electric potential VV due to a point charge qq at a distance rr is given by

V=14πε0qrV = \dfrac{1}{4 \pi \varepsilon_0} \dfrac{q}{r}

Substituting the given values:

3×104=9×109×q0.63 \times 10^4 = \dfrac{9 \times 10^9 \times q}{0.6}

q=3×104×0.69×109q = \dfrac{3 \times 10^4 \times 0.6}{9 \times 10^9}

q=1.8×1049×109q = \dfrac{1.8 \times 10^4}{9 \times 10^9}

q=0.2×10−5 Cq = 0.2 \times 10^{-5} \text{ C}

q=2×10−6 Cq = 2 \times 10^{-6} \text{ C}

Answer: 2×10−6 C2 \times 10^{-6} \text{ C}
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