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NEET2026PhysicsChapterActual

In the circuit shown below, D₁ and D₂ are silicon diodes. Assuming the knee voltage (barrier potential) of a silicon diode to be 0.7 V , what is the current supplied by the battery?

Options

  1. A0.30 A
  2. B0.37 A
  3. C0.40 A
  4. D0.60 A

Correct answer

A. 0.30 A

Step-by-step solution

The positive terminal of the battery is connected to the p-side of diode D₁ and the n-side of diode D₂ . Therefore, D₁ is forward-biased and D₂ is reverse-biased. The branch containing D₂ acts as an open circuit, so no current flows through R₃ . The active circuit is a series loop with the battery, R₁ , D₁ , and R₂ . The net voltage driving the current is the battery voltage minus the barrier potential of the forward-biased diode D₁ . V_ net = 3.7 - 0.7 = 3.0 V The equivalent resistance of the active circuit is the

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