A stone is dropped from a very high cliff. If the distance covered by the stone in the n^ th second of its descent is exactly equal to the total distance covered by it in the first 3 seconds of its fall, what is the

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Correct answer: C. 5

Distance covered in the n^ th second is given by S_n = u + (1)/(2)g(2n - 1) . Since the stone is dropped, u = 0 . S_n = (1)/(2)g(2n - 1) Total distance covered in the first 3 seconds is given by S = ut + (1)/(2)gt^2 . S = 0 + (1)/(2)g(3)^2 = (9)/(2)g Given that S_n = S , we have: (1)/(2)g(2n - 1) = (9)/(2)g 2n - 1 = 9 2n = 10 n = 5 Answer: 5

A stone is dropped from a very high cliff. If the distance covered...

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