A rectangular loop of sides 50 cm and 40 cm has a resistance of 5 . It is placed in a uniform magnetic field of 1.5 T . If the plane of the loop makes an angle of 30^ with the direction of the magnetic field, the magnetic flux through the loop is:

Step-by-step solution

The area of the rectangular loop is given by: A = 50 cm 40 cm = 2000 cm ^2 = 0.2 m ^2 The plane of the loop makes an angle of 30^ with the magnetic field. The angle between the area vector (normal to the plane) and the magnetic field is: = 90^ - 30^ = 60^ The magnetic flux through the loop is: = BA Substituting the given values: = 1.5 0.2 60^ = 0.3 1 2 = 0.15 Wb Answer: 0.15 Wb