A rectangular loop of sides 50 cm and 40 cm has a resistance of 5\...

The area of the rectangular loop is given by:

$A = 50\text{ cm} \times 40\text{ cm} = 2000\text{ cm}^2 = 0.2\text{ m}^2$

The plane of the loop makes an angle of $30^\circ$ with the magnetic field. The angle $\theta$ between the area vector (normal to the plane) and the magnetic field is:

$\theta = 90^\circ - 30^\circ = 60^\circ$

The magnetic flux $\Phi$ through the loop is:

$\Phi = BA \cos\theta$

Substituting the given values:

$\Phi = 1.5 \times 0.2 \times \cos 60^\circ$

$\Phi = 0.3 \times \dfrac{1}{2} = 0.15\text{ Wb}$

Answer: $0.15\text{ Wb}$