The alternating current flowing through a circuit is given by the...

The given equation for the alternating current is $i = 10 \sin(50\pi t)$ A.

Comparing this with the standard equation of alternating current $i = I_0 \sin(\omega t)$, the peak value of the current is $I_0 = 10$ A.

The root mean square (rms) value of the current is given by the relation:

$I_{rms} = \dfrac{I_0}{\sqrt{2}}$

Substituting the value of $I_0$:

$I_{rms} = \dfrac{10}{\sqrt{2}} = 5\sqrt{2}$ A.

Answer: $5\sqrt{2}\text{ A}$