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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

An electromagnetic wave travels through a medium having relative...

An electromagnetic wave travels through a medium having relative permittivity ϵr\epsilon_r and relative permeability μr\mu_r. If a new medium is chosen such that its relative permittivity is 2ϵr2\epsilon_r and relative permeability is μr2\dfrac{\mu_r}{2}, the speed of the electromagnetic wave in the new medium compared to the original medium will:

Options

  1. Aremain the same
  2. Bbe doubled
  3. Cbe halved
  4. Dincrease by a factor of 2\sqrt{2}

Correct answer

A. remain the same

Step-by-step solution

The speed of an electromagnetic wave in a medium is given by v=1μϵ=cμrϵrv = \dfrac{1}{\sqrt{\mu \epsilon}} = \dfrac{c}{\sqrt{\mu_r \epsilon_r}}.

For the original medium, v1=cμrϵrv_1 = \dfrac{c}{\sqrt{\mu_r \epsilon_r}}.

For the new medium, the relative permittivity is 2ϵr2\epsilon_r and the relative permeability is μr2\dfrac{\mu_r}{2}.

The speed in the new medium is v2=c(μr2)(2ϵr)=cμrϵrv_2 = \dfrac{c}{\sqrt{\left(\dfrac{\mu_r}{2}\right) (2\epsilon_r)}} = \dfrac{c}{\sqrt{\mu_r \epsilon_r}}.

Thus, v2=v1v_2 = v_1.

The speed of the electromagnetic wave remains the same.

Answer: remain the same
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