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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Chapter

NEET 2026 · Physics · Chapter

In the circuit shown, an alternating voltage source is connected to...

In the circuit shown, an alternating voltage source is connected to a resistor, an inductor, and a capacitor in series.
In the circuit shown, an alternating voltage source is connected to a resistor, an inductor, and a capacitor in series. The readings of the ideal voltmeters V1V_1, V2V_2, and V3V_3 connected across the resistor, inductor, and capacitor are 16 V16\text{ V}, 24 V24\text{ V}, and 12 V12\text{ V} respectively. If the amplitude of the current in the circuit is 22 A2\sqrt{2}\text{ A}, what is the impedance of the circuit?

Options

  1. A102 Ω10\sqrt{2}\ \Omega
  2. B26 Ω26\ \Omega
  3. C10 Ω10\ \Omega
  4. D52 Ω5\sqrt{2}\ \Omega

Correct answer

C. 10 Ω10\ \Omega

Step-by-step solution

The readings of the AC voltmeters give the RMS voltage across the respective components.

VR=16 VV_R = 16\text{ V}
VL=24 VV_L = 24\text{ V}
VC=12 VV_C = 12\text{ V}

The total RMS voltage of the source is:
Vrms=VR2+(VL−VC)2V_{\text{rms}} = \sqrt{V_R^2 + (V_L - V_C)^2}
Vrms=162+(24−12)2=162+122=20 VV_{\text{rms}} = \sqrt{16^2 + (24 - 12)^2} = \sqrt{16^2 + 12^2} = 20\text{ V}

The amplitude of the current is I0=22 AI_0 = 2\sqrt{2}\text{ A}.
The RMS current is:
Irms=I02=222=2 AI_{\text{rms}} = \dfrac{I_0}{\sqrt{2}} = \dfrac{2\sqrt{2}}{\sqrt{2}} = 2\text{ A}

The impedance of the circuit is:
Z=VrmsIrms=202=10 ΩZ = \dfrac{V_{\text{rms}}}{I_{\text{rms}}} = \dfrac{20}{2} = 10\ \Omega

Answer: 10 Ω10\ \Omega
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