A square coil of side length 10 cm is placed with its plane perpendicular to a uniform magnetic field. The variation of the magnetic field B with time t is described by a straight-line graph, which shows the field decreasing linearly from 4 T at t = 0 to 0 at t = 2 s . If the average induced emf in the coil is 12 V , the number of turns in the coil is:

Step-by-step solution

Area of the square coil, A = a^2 = (0.1 m )^2 = 0.01 m ^2 From the given graph description, the magnitude of the rate of change of the magnetic field is: | B| t = 4 - 0 2 = 2 T/s According to Faraday's law, the average induced EMF is given by: = N A ( | B| t ) Substituting the given values: 12 = N 0.01 2 12 = N 0.02 N = 12 0.02 = 600 Answer: 600