Two projectiles A and B are fired simultaneously from the same point on level ground, in the same vertical plane and forward direction. Projectile A is fired at an angle of 60^ to the horizontal with an initial speed of 20 m/s . Projectile B is fired at an angle of 30^ to the horizontal. An observer notices that during the flight, both projectiles are always at the exact same vertical height from the ground. The magn

Step-by-step solution

For both projectiles to always be at the same vertical height, their vertical components of initial velocity must be identical. Thus, v_A 60^ = v_B 30^ . Substituting the given values, we get 20 3 2 = v_B 1 2 , which gives v_B = 20 3 m/s . Since their vertical velocities are identical at all times, their relative velocity is purely horizontal and constant. The horizontal components of their velocities are: v_ Ax = 20 60^ = 10 m/s v_ Bx = 20 3 30^ = 20 3 3 2 = 30 m/s The magnitude of the relative velocity is |v_ Ax