JEE MainPhysicsElectromagnetic Waves
The magnetic field of an electromagnetic wave travelling in a vacuum is given by the equation B = 3 10⁻⁸ ( t - kx) T. The RMS value of the corresponding electric field is (Given c = 3 10^8 m s ⁻¹ )
Options
- A9 V m ⁻¹
- B9 2 V m ⁻¹
- C9 2 V m ⁻¹
- D10⁻¹⁶ 2 V m ⁻¹
Correct answer
C. 9 2 V m ⁻¹
Step-by-step solution
Given the magnetic field equation, B = 3 10⁻⁸ ( t - kx) T. The peak value of the magnetic field is B₀ = 3 10⁻⁸ T. The peak value of the electric field is related to the peak magnetic field by: E₀ = cB₀ E₀ = (3 10^8) (3 10⁻⁸) = 9 V m ⁻¹ The RMS value of the electric field is given by: E_ rms = E₀ 2 = 9 2 V m ⁻¹ Answer: 9 2 V m ⁻¹