A sound wave of frequency 200 Hz travels through a medium with a speed of 300 m s ⁻¹ . The minimum distance between two points where the phase difference is 60^ is ______ cm .

Step-by-step solution

The wavelength of the sound wave is given by = v f . Substituting the given values: = 300 200 = 1.5 m The relation between phase difference and path difference x is: = 2 x Given = 60^ = 3 rad , we have: 3 = 2 1.5 x x = 1.5 6 = 0.25 m Converting to centimeters: x = 0.25 100 = 25 cm Answer: 25