A projectile launcher has a maximum horizontal range of 400 m . It needs to hit a target on the ground that is at a distance of 200 m from the launcher. The possible angles of projection to hit the target are

Step-by-step solution

The maximum horizontal range is given by R_ max = u^2 g . Given R_ max = 400 m , we have u^2 g = 400 m . The horizontal range for an angle of projection is R = u^2 (2 ) g . For the target at 200 m , 200 = ( u^2 g ) (2 ) Substituting the value of u^2 g , 200 = 400 (2 ) (2 ) = 1 2 The possible values for 2 in the range 0^ to 180^ are 30^ and 150^ . Therefore, = 15^ or = 75^ . Answer: 15^ and 75^