An electromagnetic wave propagates through a transparent non-magnetic medium. The electric field of the wave is given by E = 60 (10^3 x - 2 10¹¹ t) j V/m . The amplitude of the magnetic field and the refractive index of the medium are respectively (Take the speed of light in vacuum c = 3 10^8 m/s )

Step-by-step solution

From the given equation of the electric field, the angular frequency is = 2 10¹¹ rad/s and the wave number is k = 10^3 rad/m . The speed of the electromagnetic wave in the medium is: v = k = 2 10¹¹ 10^3 = 2 10^8 m/s The refractive index of the medium is: n = c v = 3 10^8 2 10^8 = 1.5 The amplitude of the magnetic field in the medium is related to the electric field amplitude by E₀ = v B₀ . B₀ = E₀ v = 60 2 10^8 = 3 10⁻⁷ T Answer: 3 10⁻⁷ T and 1.5