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The equation of a progressive transverse wave is given by y = A ( t - kx) . If the maximum speed of a particle in the medium is equal to 4 times the wave propagation speed, then the wavelength of the wave is:

Options

  1. AA 2
  2. B2 A
  3. CA 4
  4. DA 2

Correct answer

A. A 2

Step-by-step solution

The maximum velocity of a particle in the medium is v_ p, max = A . The wave propagation speed is v_w = k . We know that the wave number k = 2 , so v_w = 2 . According to the given condition, v_ p, max = 4 v_w . Substituting the expressions, we get: A = 4 ( 2 ) A = 2 Rearranging for wavelength , we obtain = A 2 . Answer: A 2

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