A plane electromagnetic wave travels in free space along the -y direction. At a particular point in space and time, the magnetic field vector of the wave is B = 2 10⁻⁷ i T . The electric field vector E of the wave at that point is (Speed of light in vacuum c = 3 10^8 m/s )

Step-by-step solution

The magnitude of the electric field is given by E = cB . Substituting the given values: E = (3 10^8 m/s ) (2 10⁻⁷ T ) = 60 V/m The direction of propagation of an electromagnetic wave is given by the direction of E B . Let the direction of the electric field be E . Given the direction of propagation v = - j and the direction of the magnetic field B = i . Therefore, E i = - j . Since k i = j , we must have (- k ) i = - j . Thus, E = - k . The electric field vector is E = -60 k V/m . Answer: -60 k V/m