JEE MainPhysicsElectrostatics
The electric potential at a point due to a point charge at a distance of 45 cm is -40 V . The value of the point charge is: (Assume 1 4 ₀ = 9 10^9 N m ^2 C ⁻² )
Options
- A-200 nC
- B+2 nC
- C-2 nC
- D-0.9 nC
Correct answer
C. -2 nC
Step-by-step solution
The electric potential due to a point charge is given by V = 1 4 ₀ Q r Given data: V = -40 V r = 45 cm = 0.45 m Rearranging the formula to solve for the charge Q : Q = V r 1 4 ₀ Substituting the values: Q = -40 0.45 9 10^9 Q = -18 9 10^9 Q = -2 10⁻⁹ C Q = -2 nC Answer: -2 nC